Problem Description读入两个小于100的正整数A和B,计算A+B.需要注意的是:A和B的每一位数字由对应的英文单词给出. Input测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.  Output对每个测试用例输出1行,即A+B的值. Sample Inputone + two = three four + five six = zero seven + eight nine = zero + zero = Sample Output3 90 96

#include
      
       #include
       
        int searchs(char a[]){    char x[11][11]={
    "zero","one","two","three","four","five","six","seven","eight","nine"};    int i;    for(i=0;i<10;i++){        if(strcmp(x[i],a)==0)            break;    }    return i;}int main(){    int a,b;    char s[10];    while(true){        a=b=0;        while(scanf("%s",s)&&strcmp(s,"+")){            a=a*10+searchs(s);        }        while(scanf("%s",s)&&strcmp(s,"=")){            b=b*10+searchs(s);        }        if(a==0&&b==0)            break;        printf("%d\n",a+b);    }    return 0;}
       
      

strcmp(char s1[],char s2)

s1=s2 return 0

s1<s2 return 负数

s1>s2 return 正数